Base | Representation |
---|---|
bin | 100111000000100111011… |
… | …1101110011100001100111 |
3 | 200222112211020210021100121 |
4 | 1032001032331303201213 |
5 | 1200320214131310322 |
6 | 15223002520022411 |
7 | 1062231403104244 |
oct | 116011675634147 |
9 | 20875736707317 |
10 | 5361444010087 |
11 | 1787859409a90 |
12 | 727100901a07 |
13 | 2cb77486a699 |
14 | 1476d10685cb |
15 | 946e42bcec7 |
hex | 4e04ef73867 |
5361444010087 has 16 divisors (see below), whose sum is σ = 6037873588224. Its totient is φ = 4716537084000.
The previous prime is 5361444010033. The next prime is 5361444010093. The reversal of 5361444010087 is 7800104441635.
It is a cyclic number.
It is not a de Polignac number, because 5361444010087 - 215 = 5361443977319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5361544010087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5492973 + ... + 6394969.
It is an arithmetic number, because the mean of its divisors is an integer number (377367099264).
Almost surely, 25361444010087 is an apocalyptic number.
5361444010087 is a deficient number, since it is larger than the sum of its proper divisors (676429578137).
5361444010087 is a wasteful number, since it uses less digits than its factorization.
5361444010087 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 919470.
The product of its (nonzero) digits is 322560, while the sum is 43.
The spelling of 5361444010087 in words is "five trillion, three hundred sixty-one billion, four hundred forty-four million, ten thousand, eighty-seven".
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