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53620117 is a prime number
BaseRepresentation
bin1100110010001…
…0110110010101
310201220011222021
43030202312111
5102211320432
65153133141
71220522605
oct314426625
9121804867
1053620117
11282a3651
1215b5a1b1
13b1550a5
14719ac05
154a92697
hex3322d95

53620117 has 2 divisors, whose sum is σ = 53620118. Its totient is φ = 53620116.

The previous prime is 53620103. The next prime is 53620129. The reversal of 53620117 is 71102635.

53620117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46362481 + 7257636 = 6809^2 + 2694^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53620117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53620091 and 53620100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53620187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26810058 + 26810059.

It is an arithmetic number, because the mean of its divisors is an integer number (26810059).

Almost surely, 253620117 is an apocalyptic number.

It is an amenable number.

53620117 is a deficient number, since it is larger than the sum of its proper divisors (1).

53620117 is an equidigital number, since it uses as much as digits as its factorization.

53620117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 53620117 is about 7322.5758446055. The cubic root of 53620117 is about 377.0878902562.

The spelling of 53620117 in words is "fifty-three million, six hundred twenty thousand, one hundred seventeen".