Base | Representation |
---|---|
bin | 100111000001001001011… |
… | …1111110100110101100101 |
3 | 200222122202210111101211220 |
4 | 1032002102333310311211 |
5 | 1200330033324443222 |
6 | 15223312051450553 |
7 | 1062301602504612 |
oct | 116022277646545 |
9 | 20878683441756 |
10 | 5362585390437 |
11 | 1788294717a30 |
12 | 72737abb6a59 |
13 | 2cb8c7179282 |
14 | 14779c899509 |
15 | 9475e5c9b5c |
hex | 4e092ff4d65 |
5362585390437 has 16 divisors (see below), whose sum is σ = 7800867648000. Its totient is φ = 3249741983600.
The previous prime is 5362585390427. The next prime is 5362585390523. The reversal of 5362585390437 is 7340935852635.
It is a cyclic number.
It is not a de Polignac number, because 5362585390437 - 26 = 5362585390373 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5362585390417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7392489 + ... + 8085422.
It is an arithmetic number, because the mean of its divisors is an integer number (487554228000).
Almost surely, 25362585390437 is an apocalyptic number.
It is an amenable number.
5362585390437 is a deficient number, since it is larger than the sum of its proper divisors (2438282257563).
5362585390437 is a wasteful number, since it uses less digits than its factorization.
5362585390437 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15488424.
The product of its (nonzero) digits is 81648000, while the sum is 60.
The spelling of 5362585390437 in words is "five trillion, three hundred sixty-two billion, five hundred eighty-five million, three hundred ninety thousand, four hundred thirty-seven".
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