5363000143 has 4 divisors (see below), whose sum is σ = 5363186920. Its totient is φ = 5362813368.

The previous prime is 5363000141. The next prime is 5363000161. The reversal of 5363000143 is 3410003635.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3410003635 = 5 ⋅682000727.

It is a cyclic number.

It is not a de Polignac number, because 5363000143 - 2¹ = 5363000141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5363000141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40233 + ... + 111106.

It is an arithmetic number, because the mean of its divisors is an integer number (1340796730).

Almost surely, 2^5363000143 is an apocalyptic number.

5363000143 is a deficient number, since it is larger than the sum of its proper divisors (186777).

5363000143 is a wasteful number, since it uses less digits than its factorization.

5363000143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 186776.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 5363000143 is about 73232.5074198610. The cubic root of 5363000143 is about 1750.3944844565.

Adding to 5363000143 its reverse (3410003635), we get a palindrome (8773003778).

The spelling of 5363000143 in words is "five billion, three hundred sixty-three million, one hundred forty-three", and thus it is an aban number.