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53640023517301 = 134126155655177
BaseRepresentation
bin11000011001001000010101…
…00011000010100001110101
321000220221021110120221020211
430030210022203002201311
524012314232010023201
6310025515302025421
714204235534002464
oct1414441243024165
9230827243527224
1053640023517301
1116100673979291
126023967418271
1323c1303aa7ca0
14d362961149db
15630477d01651
hex30c90a8c2875

53640023517301 has 4 divisors (see below), whose sum is σ = 57766179172492. Its totient is φ = 49513867862112.

The previous prime is 53640023517299. The next prime is 53640023517341. The reversal of 53640023517301 is 10371532004635.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 34770469429201 + 18869554088100 = 5896649^2 + 4343910^2 .

It is a cyclic number.

It is not a de Polignac number, because 53640023517301 - 21 = 53640023517299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53640023517341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2063077827576 + ... + 2063077827601.

It is an arithmetic number, because the mean of its divisors is an integer number (14441544793123).

Almost surely, 253640023517301 is an apocalyptic number.

It is an amenable number.

53640023517301 is a deficient number, since it is larger than the sum of its proper divisors (4126155655191).

53640023517301 is a wasteful number, since it uses less digits than its factorization.

53640023517301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4126155655190.

The product of its (nonzero) digits is 226800, while the sum is 40.

The spelling of 53640023517301 in words is "fifty-three trillion, six hundred forty billion, twenty-three million, five hundred seventeen thousand, three hundred one".

Divisors: 1 13 4126155655177 53640023517301