Base | Representation |
---|---|
bin | 110001111101010011… |
… | …000110000000101011 |
3 | 12010110101102222220121 |
4 | 301331103012000223 |
5 | 1334324242434112 |
6 | 40350453104111 |
7 | 3606202323103 |
oct | 617523060053 |
9 | 163411388817 |
10 | 53641764907 |
11 | 20827417a15 |
12 | a490628037 |
13 | 509b3b3ac3 |
14 | 284c272203 |
15 | 15de456407 |
hex | c7d4c602b |
53641764907 has 2 divisors, whose sum is σ = 53641764908. Its totient is φ = 53641764906.
The previous prime is 53641764893. The next prime is 53641764959. The reversal of 53641764907 is 70946714635.
It is an a-pointer prime, because the next prime (53641764959) can be obtained adding 53641764907 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53641764907 is a prime.
It is not a weakly prime, because it can be changed into another prime (53641764977) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26820882453 + 26820882454.
It is an arithmetic number, because the mean of its divisors is an integer number (26820882454).
Almost surely, 253641764907 is an apocalyptic number.
53641764907 is a deficient number, since it is larger than the sum of its proper divisors (1).
53641764907 is an equidigital number, since it uses as much as digits as its factorization.
53641764907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3810240, while the sum is 52.
The spelling of 53641764907 in words is "fifty-three billion, six hundred forty-one million, seven hundred sixty-four thousand, nine hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •