Base | Representation |
---|---|
bin | 111100111111000011101011… |
… | …1001010101001111010001111 |
3 | 2121100100102010011221212010211 |
4 | 1321332013113022221322033 |
5 | 1030302401010401404210 |
6 | 5140521305001343251 |
7 | 220663641336604201 |
oct | 17176072712517217 |
9 | 2540312104855124 |
10 | 536432140263055 |
11 | 145a1865846aa43 |
12 | 501b8186497b27 |
13 | 1a0424453b049a |
14 | 9667650170771 |
15 | 4203c6e9ee38a |
hex | 1e7e1d72a9e8f |
536432140263055 has 4 divisors (see below), whose sum is σ = 643718568315672. Its totient is φ = 429145712210440.
The previous prime is 536432140262971. The next prime is 536432140263073. The reversal of 536432140263055 is 550362041234635.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-536432140263055 is a prime.
It is a super-2 number, since 2×5364321402630552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53643214026301 + ... + 53643214026310.
It is an arithmetic number, because the mean of its divisors is an integer number (160929642078918).
Almost surely, 2536432140263055 is an apocalyptic number.
536432140263055 is a deficient number, since it is larger than the sum of its proper divisors (107286428052617).
536432140263055 is a wasteful number, since it uses less digits than its factorization.
536432140263055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107286428052616.
The product of its (nonzero) digits is 7776000, while the sum is 49.
The spelling of 536432140263055 in words is "five hundred thirty-six trillion, four hundred thirty-two billion, one hundred forty million, two hundred sixty-three thousand, fifty-five".
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