Base | Representation |
---|---|
bin | 100111000010110110100… |
… | …1101001111011011111001 |
3 | 201000000012221012221000020 |
4 | 1032011231031033123321 |
5 | 1200410033030342340 |
6 | 15225115230401053 |
7 | 1062461405201142 |
oct | 116055515173371 |
9 | 21000187187006 |
10 | 5366246340345 |
11 | 17898a3185870 |
12 | 728021060189 |
13 | 2cc05b779817 |
14 | 147a28b92ac9 |
15 | 948c5bca9d0 |
hex | 4e16d34f6f9 |
5366246340345 has 64 divisors (see below), whose sum is σ = 9375454771200. Its totient is φ = 2599341373440.
The previous prime is 5366246340223. The next prime is 5366246340353. The reversal of 5366246340345 is 5430436426635.
It is not a de Polignac number, because 5366246340345 - 214 = 5366246323961 is a prime.
It is a super-2 number, since 2×53662463403452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1420015666 + ... + 1420019444.
It is an arithmetic number, because the mean of its divisors is an integer number (146491480800).
Almost surely, 25366246340345 is an apocalyptic number.
5366246340345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5366246340345 is a deficient number, since it is larger than the sum of its proper divisors (4009208430855).
5366246340345 is a wasteful number, since it uses less digits than its factorization.
5366246340345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9710.
The product of its (nonzero) digits is 18662400, while the sum is 51.
The spelling of 5366246340345 in words is "five trillion, three hundred sixty-six billion, two hundred forty-six million, three hundred forty thousand, three hundred forty-five".
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