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53673050437 = 1721131494197
BaseRepresentation
bin110001111111001010…
…011100000101000101
312010112120022110120221
4301333022130011011
51334410300103222
640353531424341
73610032254416
oct617712340505
9163476273527
1053673050437
1120843046226
12a49abb50b1
1350a4a18c56
14285249780d
1515e20860c7
hexc7f29c145

53673050437 has 8 divisors (see below), whose sum is σ = 56857222296. Its totient is φ = 50491871232.

The previous prime is 53673050419. The next prime is 53673050477. The reversal of 53673050437 is 73405037635.

53673050437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 1433833956 + 52239216481 = 37866^2 + 228559^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53673050437 - 215 = 53673017669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53673050393 and 53673050402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53673050407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 711178 + ... + 783019.

It is an arithmetic number, because the mean of its divisors is an integer number (7107152787).

Almost surely, 253673050437 is an apocalyptic number.

It is an amenable number.

53673050437 is a deficient number, since it is larger than the sum of its proper divisors (3184171859).

53673050437 is a wasteful number, since it uses less digits than its factorization.

53673050437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1496327.

The product of its (nonzero) digits is 793800, while the sum is 43.

The spelling of 53673050437 in words is "fifty-three billion, six hundred seventy-three million, fifty thousand, four hundred thirty-seven".