Base | Representation |
---|---|
bin | 110001111111001110… |
… | …000000001100100000 |
3 | 12010112122001221021222 |
4 | 301333032000030200 |
5 | 1334411020003200 |
6 | 40354003434212 |
7 | 3610043225462 |
oct | 617716001440 |
9 | 163478057258 |
10 | 53673984800 |
11 | 20843624227 |
12 | a49b385968 |
13 | 50a4c85327 |
14 | 285265c132 |
15 | 15e21bcd85 |
hex | c7f380320 |
53673984800 has 54 divisors (see below), whose sum is σ = 131047614369. Its totient is φ = 21466972800.
The previous prime is 53673984797. The next prime is 53673984829. The reversal of 53673984800 is 848937635.
It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.
It can be written as a sum of positive squares in 2 ways, for example, as 52600505104 + 1073479696 = 229348^2 + 32764^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=163820.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 6548705 + ... + 6556895.
Almost surely, 253673984800 is an apocalyptic number.
53673984800 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53673984800 is an abundant number, since it is smaller than the sum of its proper divisors (77373629569).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53673984800 is an frugal number, since it uses more digits than its factorization.
53673984800 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16402 (or 8198 counting only the distinct ones).
The product of its (nonzero) digits is 4354560, while the sum is 53.
The spelling of 53673984800 in words is "fifty-three billion, six hundred seventy-three million, nine hundred eighty-four thousand, eight hundred".
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