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536772143 is a prime number
BaseRepresentation
bin11111111111100…
…111111000101111
31101102000211221202
4133333213320233
52044403202033
6125132520115
716205326235
oct3777477057
91342024852
10536772143
11255aa2946
1212b92003b
138728b66b
1451408955
15321cd8e8
hex1ffe7e2f

536772143 has 2 divisors, whose sum is σ = 536772144. Its totient is φ = 536772142.

The previous prime is 536772113. The next prime is 536772163. The reversal of 536772143 is 341277635.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 536772143 - 26 = 536772079 is a prime.

It is a super-3 number, since 3×5367721433 (a number of 27 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 536772097 and 536772106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (536772113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268386071 + 268386072.

It is an arithmetic number, because the mean of its divisors is an integer number (268386072).

Almost surely, 2536772143 is an apocalyptic number.

536772143 is a deficient number, since it is larger than the sum of its proper divisors (1).

536772143 is an equidigital number, since it uses as much as digits as its factorization.

536772143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 105840, while the sum is 38.

The square root of 536772143 is about 23168.3435532193. The cubic root of 536772143 is about 812.6994946192.

The spelling of 536772143 in words is "five hundred thirty-six million, seven hundred seventy-two thousand, one hundred forty-three".