Base | Representation |
---|---|
bin | 1001111111111111… |
… | …11110110010010101 |
3 | 111212011011102120102 |
4 | 10333333332302111 |
5 | 41443342013044 |
6 | 2244421543445 |
7 | 250020142454 |
oct | 47777766225 |
9 | 14764142512 |
10 | 5368704149 |
11 | 2305547986 |
12 | 1059b74b85 |
13 | 677363423 |
14 | 38d03ab9b |
15 | 2164d724e |
hex | 13fffec95 |
5368704149 has 2 divisors, whose sum is σ = 5368704150. Its totient is φ = 5368704148.
The previous prime is 5368704113. The next prime is 5368704151. The reversal of 5368704149 is 9414078635.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5072003524 + 296700625 = 71218^2 + 17225^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5368704149 is a prime.
Together with 5368704151, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5368700149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2684352074 + 2684352075.
It is an arithmetic number, because the mean of its divisors is an integer number (2684352075).
Almost surely, 25368704149 is an apocalyptic number.
It is an amenable number.
5368704149 is a deficient number, since it is larger than the sum of its proper divisors (1).
5368704149 is an equidigital number, since it uses as much as digits as its factorization.
5368704149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 47.
The square root of 5368704149 is about 73271.4415649099. The cubic root of 5368704149 is about 1751.0148289629.
The spelling of 5368704149 in words is "five billion, three hundred sixty-eight million, seven hundred four thousand, one hundred forty-nine".
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