Base | Representation |
---|---|
bin | 1100110011100… |
… | …1010100010011 |
3 | 10202001212012210 |
4 | 3030321110103 |
5 | 102222242042 |
6 | 5155123203 |
7 | 1221355116 |
oct | 314712423 |
9 | 122055183 |
10 | 53712147 |
11 | 28356805 |
12 | 15ba3503 |
13 | b187c48 |
14 | 71c257d |
15 | 4aaea9c |
hex | 3339513 |
53712147 has 24 divisors (see below), whose sum is σ = 75602800. Its totient is φ = 33909120.
The previous prime is 53712133. The next prime is 53712149. The reversal of 53712147 is 74121735.
53712147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53712147 - 210 = 53711123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53712149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 153729 + ... + 154077.
Almost surely, 253712147 is an apocalyptic number.
53712147 is a deficient number, since it is larger than the sum of its proper divisors (21890653).
53712147 is a wasteful number, since it uses less digits than its factorization.
53712147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 471 (or 442 counting only the distinct ones).
The product of its digits is 5880, while the sum is 30.
The square root of 53712147 is about 7328.8571414648. The cubic root of 53712147 is about 377.3035031343.
The spelling of 53712147 in words is "fifty-three million, seven hundred twelve thousand, one hundred forty-seven".
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