53712433 has 2 divisors, whose sum is σ = 53712434. Its totient is φ = 53712432.

The previous prime is 53712431. The next prime is 53712457. The reversal of 53712433 is 33421735.

53712433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 45319824 + 8392609 = 6732^2 + 2897^2 .

It is a cyclic number.

It is not a de Polignac number, because 53712433 - 2¹ = 53712431 is a prime.

Together with 53712431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53712431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26856216 + 26856217.

It is an arithmetic number, because the mean of its divisors is an integer number (26856217).

Almost surely, 2^53712433 is an apocalyptic number.

It is an amenable number.

53712433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53712433 is an equidigital number, since it uses as much as digits as its factorization.

53712433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7560, while the sum is 28.

The square root of 53712433 is about 7328.8766533487. The cubic root of 53712433 is about 377.3041728066.

It can be divided in two parts, 53712 and 433, that added together give a palindrome (54145).

The spelling of 53712433 in words is "fifty-three million, seven hundred twelve thousand, four hundred thirty-three".