Base | Representation |
---|---|
bin | 100111000110000000000… |
… | …0001010000000110001101 |
3 | 201000122122220201201010100 |
4 | 1032030000001100012031 |
5 | 1201012403112242443 |
6 | 15232154003401313 |
7 | 1063121025656610 |
oct | 116140001200615 |
9 | 21018586651110 |
10 | 5373004415373 |
11 | 1791750a11641 |
12 | 7293a8383239 |
13 | 2cc89790969a |
14 | 1480aa536177 |
15 | 94b6e1583d3 |
hex | 4e30005018d |
5373004415373 has 48 divisors (see below), whose sum is σ = 9020567687040. Its totient is φ = 3018078185472.
The previous prime is 5373004415341. The next prime is 5373004415381. The reversal of 5373004415373 is 3735144003735.
5373004415373 is a `hidden beast` number, since 5 + 3 + 73 + 0 + 0 + 4 + 41 + 537 + 3 = 666.
It is not a de Polignac number, because 5373004415373 - 25 = 5373004415341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5373004435373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 95249665 + ... + 95306057.
It is an arithmetic number, because the mean of its divisors is an integer number (187928493480).
Almost surely, 25373004415373 is an apocalyptic number.
It is an amenable number.
5373004415373 is a deficient number, since it is larger than the sum of its proper divisors (3647563271667).
5373004415373 is a wasteful number, since it uses less digits than its factorization.
5373004415373 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82098 (or 82095 counting only the distinct ones).
The product of its (nonzero) digits is 1587600, while the sum is 45.
The spelling of 5373004415373 in words is "five trillion, three hundred seventy-three billion, four million, four hundred fifteen thousand, three hundred seventy-three".
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