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537452163420037 is a prime number
BaseRepresentation
bin111101000110011110101010…
…1010010001100111110000101
32121110221220222100111001021121
41322030331111102030332011
51030421104012313420122
65143022040525513541
7221130431430435205
oct17214752522147605
92543856870431247
10537452163420037
111462812009a1058
12503419b61128b1
131a0b76a1aa0cb8
1496a0b759aa405
15422056e057bc7
hex1e8cf5548cf85

537452163420037 has 2 divisors, whose sum is σ = 537452163420038. Its totient is φ = 537452163420036.

The previous prime is 537452163420023. The next prime is 537452163420089. The reversal of 537452163420037 is 730024361254735.

It is an a-pointer prime, because the next prime (537452163420089) can be obtained adding 537452163420037 to its sum of digits (52).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 387778251031396 + 149673912388641 = 19692086^2 + 12234129^2 .

It is a cyclic number.

It is not a de Polignac number, because 537452163420037 - 231 = 537450015936389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (537452163420017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268726081710018 + 268726081710019.

It is an arithmetic number, because the mean of its divisors is an integer number (268726081710019).

Almost surely, 2537452163420037 is an apocalyptic number.

It is an amenable number.

537452163420037 is a deficient number, since it is larger than the sum of its proper divisors (1).

537452163420037 is an equidigital number, since it uses as much as digits as its factorization.

537452163420037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12700800, while the sum is 52.

The spelling of 537452163420037 in words is "five hundred thirty-seven trillion, four hundred fifty-two billion, one hundred sixty-three million, four hundred twenty thousand, thirty-seven".