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53760133 = 77680019
BaseRepresentation
bin1100110100010…
…1000010000101
310202011022001001
43031011002011
5102230311013
65200133301
71221645040
oct315050205
9122138031
1053760133
1128389869
1216007231
13b1a3a3b
1471d5c57
154abdddd
hex3345085

53760133 has 4 divisors (see below), whose sum is σ = 61440160. Its totient is φ = 46080108.

The previous prime is 53760127. The next prime is 53760163. The reversal of 53760133 is 33106735.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53760133 is a prime.

It is a Duffinian number.

It is a plaindrome in base 15.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53760163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3840003 + ... + 3840016.

It is an arithmetic number, because the mean of its divisors is an integer number (15360040).

Almost surely, 253760133 is an apocalyptic number.

It is an amenable number.

53760133 is a deficient number, since it is larger than the sum of its proper divisors (7680027).

53760133 is an equidigital number, since it uses as much as digits as its factorization.

53760133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7680026.

The product of its (nonzero) digits is 5670, while the sum is 28.

The square root of 53760133 is about 7332.1301816048. The cubic root of 53760133 is about 377.4158296618.

Adding to 53760133 its reverse (33106735), we get a palindrome (86866868).

The spelling of 53760133 in words is "fifty-three million, seven hundred sixty thousand, one hundred thirty-three".

Divisors: 1 7 7680019 53760133