Base | Representation |
---|---|
bin | 110010000100111100… |
… | …110101001000111101 |
3 | 12010210100000110011102 |
4 | 302010330311020331 |
5 | 1340110124140430 |
6 | 40411320502445 |
7 | 3612321463055 |
oct | 620474651075 |
9 | 163710013142 |
10 | 53770146365 |
11 | 208929338a1 |
12 | a50761aa25 |
13 | 50bbb83970 |
14 | 2861330565 |
15 | 15ea865345 |
hex | c84f3523d |
53770146365 has 32 divisors (see below), whose sum is σ = 69805139040. Its totient is φ = 39526096896.
The previous prime is 53770146361. The next prime is 53770146371. The reversal of 53770146365 is 56364107735.
53770146365 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 16 ways, for example, as 52065199684 + 1704946681 = 228178^2 + 41291^2 .
It is not a de Polignac number, because 53770146365 - 22 = 53770146361 is a prime.
It is a super-2 number, since 2×537701463652 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53770146361) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20608181 + ... + 20610789.
It is an arithmetic number, because the mean of its divisors is an integer number (2181410595).
Almost surely, 253770146365 is an apocalyptic number.
It is an amenable number.
53770146365 is a deficient number, since it is larger than the sum of its proper divisors (16034992675).
53770146365 is a wasteful number, since it uses less digits than its factorization.
53770146365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3953.
The product of its (nonzero) digits is 1587600, while the sum is 47.
The spelling of 53770146365 in words is "fifty-three billion, seven hundred seventy million, one hundred forty-six thousand, three hundred sixty-five".
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