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5388012541 is a prime number
BaseRepresentation
bin1010000010010011…
…01000101111111101
3111220111111101201001
411001021220233331
542013312400131
62250351450301
7250343231242
oct50111505775
914814441631
105388012541
11231543562a
121064526991
1367b363b02
143918255c9
1521804d261
hex141268bfd

5388012541 has 2 divisors, whose sum is σ = 5388012542. Its totient is φ = 5388012540.

The previous prime is 5388012517. The next prime is 5388012547. The reversal of 5388012541 is 1452108835.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5383303641 + 4708900 = 73371^2 + 2170^2 .

It is a cyclic number.

It is not a de Polignac number, because 5388012541 - 211 = 5388010493 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5388012541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5388012547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2694006270 + 2694006271.

It is an arithmetic number, because the mean of its divisors is an integer number (2694006271).

Almost surely, 25388012541 is an apocalyptic number.

It is an amenable number.

5388012541 is a deficient number, since it is larger than the sum of its proper divisors (1).

5388012541 is an equidigital number, since it uses as much as digits as its factorization.

5388012541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 37.

The square root of 5388012541 is about 73403.0826396276. The cubic root of 5388012541 is about 1753.1114758256. Note that the first 3 decimals are identical.

The spelling of 5388012541 in words is "five billion, three hundred eighty-eight million, twelve thousand, five hundred forty-one".