Base | Representation |
---|---|
bin | 110010001100101101… |
… | …110100010010101001 |
3 | 12011010102011110121002 |
4 | 302030231310102221 |
5 | 1340342002202312 |
6 | 40432253124345 |
7 | 3615463040201 |
oct | 621455642251 |
9 | 164112143532 |
10 | 53900428457 |
11 | 2094a428747 |
12 | a5431896b5 |
13 | 510cb6a965 |
14 | 2874765401 |
15 | 1606eec4c2 |
hex | c8cb744a9 |
53900428457 has 2 divisors, whose sum is σ = 53900428458. Its totient is φ = 53900428456.
The previous prime is 53900428451. The next prime is 53900428459. The reversal of 53900428457 is 75482400935.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37746272656 + 16154155801 = 194284^2 + 127099^2 .
It is a cyclic number.
It is not a de Polignac number, because 53900428457 - 214 = 53900412073 is a prime.
Together with 53900428459, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53900428451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26950214228 + 26950214229.
It is an arithmetic number, because the mean of its divisors is an integer number (26950214229).
Almost surely, 253900428457 is an apocalyptic number.
It is an amenable number.
53900428457 is a deficient number, since it is larger than the sum of its proper divisors (1).
53900428457 is an equidigital number, since it uses as much as digits as its factorization.
53900428457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1209600, while the sum is 47.
The spelling of 53900428457 in words is "fifty-three billion, nine hundred million, four hundred twenty-eight thousand, four hundred fifty-seven".
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