Base | Representation |
---|---|
bin | 1010000011011001… |
… | …00010101101100101 |
3 | 111221010201021120111 |
4 | 11001230202231211 |
5 | 42023133202403 |
6 | 2251315533021 |
7 | 250514061445 |
oct | 50154425545 |
9 | 14833637514 |
10 | 5397162853 |
11 | 231a615375 |
12 | 10675ba171 |
13 | 6802189b4 |
14 | 392b28125 |
15 | 218c5956d |
hex | 141b22b65 |
5397162853 has 2 divisors, whose sum is σ = 5397162854. Its totient is φ = 5397162852.
The previous prime is 5397162851. The next prime is 5397162863. The reversal of 5397162853 is 3582617935.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5074852644 + 322310209 = 71238^2 + 17953^2 .
It is a cyclic number.
It is not a de Polignac number, because 5397162853 - 21 = 5397162851 is a prime.
Together with 5397162851, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 5397162797 and 5397162806.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5397162851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2698581426 + 2698581427.
It is an arithmetic number, because the mean of its divisors is an integer number (2698581427).
Almost surely, 25397162853 is an apocalyptic number.
It is an amenable number.
5397162853 is a deficient number, since it is larger than the sum of its proper divisors (1).
5397162853 is an equidigital number, since it uses as much as digits as its factorization.
5397162853 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1360800, while the sum is 49.
The square root of 5397162853 is about 73465.3854070065. The cubic root of 5397162853 is about 1754.1033347257.
The spelling of 5397162853 in words is "five billion, three hundred ninety-seven million, one hundred sixty-two thousand, eight hundred fifty-three".
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