Base | Representation |
---|---|
bin | 11000100010110111111011… |
… | …01001010001100000010111 |
3 | 21002002221102121212211200212 |
4 | 30101123331221101200113 |
5 | 24033310410002344131 |
6 | 310443404254400035 |
7 | 14240360135244206 |
oct | 1421337551214027 |
9 | 232087377784625 |
10 | 53974814496791 |
11 | 1621a6547323a1 |
12 | 607882020001b |
13 | 2416a59735496 |
14 | d48575ab323d |
15 | 63901ea03a2b |
hex | 3116fda51817 |
53974814496791 has 2 divisors, whose sum is σ = 53974814496792. Its totient is φ = 53974814496790.
The previous prime is 53974814496703. The next prime is 53974814496809. The reversal of 53974814496791 is 19769441847935.
53974814496791 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53974814496791 - 234 = 53957634627607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53974814436791) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26987407248395 + 26987407248396.
It is an arithmetic number, because the mean of its divisors is an integer number (26987407248396).
Almost surely, 253974814496791 is an apocalyptic number.
53974814496791 is a deficient number, since it is larger than the sum of its proper divisors (1).
53974814496791 is an equidigital number, since it uses as much as digits as its factorization.
53974814496791 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1646023680, while the sum is 77.
The spelling of 53974814496791 in words is "fifty-three trillion, nine hundred seventy-four billion, eight hundred fourteen million, four hundred ninety-six thousand, seven hundred ninety-one".
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