Base | Representation |
---|---|
bin | 1100110111110… |
… | …1011110100111 |
3 | 10202121001012002 |
4 | 3031331132213 |
5 | 102310210320 |
6 | 5205115515 |
7 | 1223630066 |
oct | 315753647 |
9 | 122531162 |
10 | 53991335 |
11 | 28527542 |
12 | 160b8b9b |
13 | b255048 |
14 | 72561dd |
15 | 4b17675 |
hex | 337d7a7 |
53991335 has 4 divisors (see below), whose sum is σ = 64789608. Its totient is φ = 43193064.
The previous prime is 53991323. The next prime is 53991341. The reversal of 53991335 is 53319935.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53991335 - 24 = 53991319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5399129 + ... + 5399138.
It is an arithmetic number, because the mean of its divisors is an integer number (16197402).
Almost surely, 253991335 is an apocalyptic number.
53991335 is a deficient number, since it is larger than the sum of its proper divisors (10798273).
53991335 is a wasteful number, since it uses less digits than its factorization.
53991335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10798272.
The product of its digits is 54675, while the sum is 38.
The square root of 53991335 is about 7347.8796261234. The cubic root of 53991335 is about 377.9560968205.
The spelling of 53991335 in words is "fifty-three million, nine hundred ninety-one thousand, three hundred thirty-five".
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