Base | Representation |
---|---|
bin | 10100100110010111001101 |
3 | 101011100102111 |
4 | 110212113031 |
5 | 2340300023 |
6 | 311424021 |
7 | 63620323 |
oct | 24462715 |
9 | 11140374 |
10 | 5400013 |
11 | 3059123 |
12 | 1985011 |
13 | 1170b98 |
14 | a07d13 |
15 | 71a00d |
hex | 5265cd |
5400013 has 4 divisors (see below), whose sum is σ = 5404960. Its totient is φ = 5395068.
The previous prime is 5400001. The next prime is 5400019. The reversal of 5400013 is 3100045.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 5400013 - 221 = 3302861 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5399966 and 5400002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5400019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33 + ... + 3286.
It is an arithmetic number, because the mean of its divisors is an integer number (1351240).
Almost surely, 25400013 is an apocalyptic number.
It is an amenable number.
5400013 is a deficient number, since it is larger than the sum of its proper divisors (4947).
5400013 is a wasteful number, since it uses less digits than its factorization.
5400013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4946.
The product of its (nonzero) digits is 60, while the sum is 13.
The square root of 5400013 is about 2323.7928048774. The cubic root of 5400013 is about 175.4412050787.
Adding to 5400013 its reverse (3100045), we get a palindrome (8500058).
Subtracting from 5400013 its reverse (3100045), we obtain a cube (2299968 = 1323).
The spelling of 5400013 in words is "five million, four hundred thousand, thirteen".
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