Base | Representation |
---|---|
bin | 1010000011110110… |
… | …10001101001101011 |
3 | 111221101222111121211 |
4 | 11001323101221223 |
5 | 42030130301011 |
6 | 2251534413551 |
7 | 250561645645 |
oct | 50173215153 |
9 | 14841874554 |
10 | 5401025131 |
11 | 2321813137 |
12 | 10689612b7 |
13 | 680c6b978 |
14 | 393451895 |
15 | 21926db21 |
hex | 141ed1a6b |
5401025131 has 4 divisors (see below), whose sum is σ = 5401818064. Its totient is φ = 5400232200.
The previous prime is 5401025129. The next prime is 5401025143. The reversal of 5401025131 is 1315201045.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5401025131 - 21 = 5401025129 is a prime.
It is a super-2 number, since 2×54010251312 = 58342144931387134322, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5401022131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386160 + ... + 399901.
It is an arithmetic number, because the mean of its divisors is an integer number (1350454516).
Almost surely, 25401025131 is an apocalyptic number.
5401025131 is a deficient number, since it is larger than the sum of its proper divisors (792933).
5401025131 is an equidigital number, since it uses as much as digits as its factorization.
5401025131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 792932.
The product of its (nonzero) digits is 600, while the sum is 22.
The square root of 5401025131 is about 73491.6670854594. The cubic root of 5401025131 is about 1754.5216544672.
Adding to 5401025131 its reverse (1315201045), we get a palindrome (6716226176).
The spelling of 5401025131 in words is "five billion, four hundred one million, twenty-five thousand, one hundred thirty-one".
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