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5401200050143 = 31211730599183
BaseRepresentation
bin100111010011001000010…
…0111000011111111011111
3201010100102220210100201121
41032212100213003333133
51201443124203101033
615253135501551411
71065136525630462
oct116462047037737
921110386710647
105401200050143
1117a26aa68a337
12732956b75567
1330243c213841
141495c308d2d9
159576e66562d
hex4e9909c3fdf

5401200050143 has 4 divisors (see below), whose sum is σ = 5402930652448. Its totient is φ = 5399469447840.

The previous prime is 5401200050123. The next prime is 5401200050209. The reversal of 5401200050143 is 3410500021045.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5401200050143 - 29 = 5401200049631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5401200050123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865296471 + ... + 865302712.

It is an arithmetic number, because the mean of its divisors is an integer number (1350732663112).

Almost surely, 25401200050143 is an apocalyptic number.

5401200050143 is a deficient number, since it is larger than the sum of its proper divisors (1730602305).

5401200050143 is a wasteful number, since it uses less digits than its factorization.

5401200050143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1730602304.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 5401200050143 its reverse (3410500021045), we get a palindrome (8811700071188).

The spelling of 5401200050143 in words is "five trillion, four hundred one billion, two hundred million, fifty thousand, one hundred forty-three".

Divisors: 1 3121 1730599183 5401200050143