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54013440000 = 21235413541
BaseRepresentation
bin110010010011011100…
…111011000000000000
312011102021211001021210
4302103130323000000
51341104420040000
640451411250120
73621334444002
oct622334730000
9164367731253
1054013440000
11209a81a6a13
12a574ba9940
13512a3b89b0
142885782372
151611dc2350
hexc9373b000

54013440000 has 520 divisors, whose sum is σ = 194166934192. Its totient is φ = 13271040000.

The previous prime is 54013439983. The next prime is 54013440007. The reversal of 54013440000 is 4431045.

It is a tau number, because it is divible by the number of its divisors (520).

It is not an unprimeable number, because it can be changed into a prime (54013440007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 99839730 + ... + 99840270.

Almost surely, 254013440000 is an apocalyptic number.

54013440000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 54013440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (97083467096).

54013440000 is an abundant number, since it is smaller than the sum of its proper divisors (140153494192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

54013440000 is an equidigital number, since it uses as much as digits as its factorization.

54013440000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601 (or 564 counting only the distinct ones).

The product of its (nonzero) digits is 960, while the sum is 21.

Adding to 54013440000 its reverse (4431045), we get a palindrome (54017871045).

The spelling of 54013440000 in words is "fifty-four billion, thirteen million, four hundred forty thousand".