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5401525103333 = 43112532540843
BaseRepresentation
bin100111010011010001111…
…1111000010101011100101
3201010101021120102202212122
41032212203333002223211
51201444310411301313
615253232032555325
71065150553553432
oct116464377025345
921111246382778
105401525103333
1117a2857115637
12732a279b2b45
13302491673ac8
14149614304b89
159578ce72708
hex4e9a3fc2ae5

5401525103333 has 4 divisors (see below), whose sum is σ = 5414057644608. Its totient is φ = 5388992562060.

The previous prime is 5401525103297. The next prime is 5401525103341. The reversal of 5401525103333 is 3333015251045.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5401525103333 - 212 = 5401525099237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5401525103293 and 5401525103302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5401525103353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6266269991 + ... + 6266270852.

It is an arithmetic number, because the mean of its divisors is an integer number (1353514411152).

Almost surely, 25401525103333 is an apocalyptic number.

It is an amenable number.

5401525103333 is a deficient number, since it is larger than the sum of its proper divisors (12532541275).

5401525103333 is a wasteful number, since it uses less digits than its factorization.

5401525103333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12532541274.

The product of its (nonzero) digits is 81000, while the sum is 35.

The spelling of 5401525103333 in words is "five trillion, four hundred one billion, five hundred twenty-five million, one hundred three thousand, three hundred thirty-three".

Divisors: 1 431 12532540843 5401525103333