Base | Representation |
---|---|
bin | 100111010011011000100… |
… | …1101111001110110000111 |
3 | 201010101212001011112022122 |
4 | 1032212301031321312013 |
5 | 1202000234224244421 |
6 | 15253310043120155 |
7 | 1065156220536212 |
oct | 116466115716607 |
9 | 21111761145278 |
10 | 5401747103111 |
11 | 17a2960464327 |
12 | 732a8a21305b |
13 | 3024c8661818 |
14 | 1496359b2779 |
15 | 957a26c52ab |
hex | 4e9b1379d87 |
5401747103111 has 4 divisors (see below), whose sum is σ = 5470123648800. Its totient is φ = 5333370557424.
The previous prime is 5401747103083. The next prime is 5401747103153. The reversal of 5401747103111 is 1113017471045.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5401747103111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5401747103161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34188272726 + ... + 34188272883.
It is an arithmetic number, because the mean of its divisors is an integer number (1367530912200).
Almost surely, 25401747103111 is an apocalyptic number.
5401747103111 is a deficient number, since it is larger than the sum of its proper divisors (68376545689).
5401747103111 is an equidigital number, since it uses as much as digits as its factorization.
5401747103111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68376545688.
The product of its (nonzero) digits is 11760, while the sum is 35.
The spelling of 5401747103111 in words is "five trillion, four hundred one billion, seven hundred forty-seven million, one hundred three thousand, one hundred eleven".
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