Base | Representation |
---|---|
bin | 110010010100010011… |
… | …010011110011000001 |
3 | 12011110021122101200121 |
4 | 302110103103303001 |
5 | 1341122042303340 |
6 | 40453041020241 |
7 | 3621566564416 |
oct | 622423236301 |
9 | 164407571617 |
10 | 54027697345 |
11 | 20a05254746 |
12 | a579924681 |
13 | 513033b2ab |
14 | 288761410d |
15 | 161328b94a |
hex | c944d3cc1 |
54027697345 has 4 divisors (see below), whose sum is σ = 64833236820. Its totient is φ = 43222157872.
The previous prime is 54027697343. The next prime is 54027697411. The reversal of 54027697345 is 54379672045.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11963328129 + 42064369216 = 109377^2 + 205096^2 .
It is a cyclic number.
It is not a de Polignac number, because 54027697345 - 21 = 54027697343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54027697292 and 54027697301.
It is not an unprimeable number, because it can be changed into a prime (54027697343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5402769730 + ... + 5402769739.
It is an arithmetic number, because the mean of its divisors is an integer number (16208309205).
Almost surely, 254027697345 is an apocalyptic number.
It is an amenable number.
54027697345 is a deficient number, since it is larger than the sum of its proper divisors (10805539475).
54027697345 is a wasteful number, since it uses less digits than its factorization.
54027697345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10805539474.
The product of its (nonzero) digits is 6350400, while the sum is 52.
The spelling of 54027697345 in words is "fifty-four billion, twenty-seven million, six hundred ninety-seven thousand, three hundred forty-five".
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