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54040013 is a prime number
BaseRepresentation
bin1100111000100…
…1010111001101
310202200111221222
43032021113031
5102313240023
65210133125
71224222026
oct316112715
9122614858
1054040013
1128560075
12161211a5
13b271251
147269c4d
154b26cc8
hex33895cd

54040013 has 2 divisors, whose sum is σ = 54040014. Its totient is φ = 54040012.

The previous prime is 54040001. The next prime is 54040039. The reversal of 54040013 is 31004045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 45670564 + 8369449 = 6758^2 + 2893^2 .

It is a cyclic number.

It is not a de Polignac number, because 54040013 - 210 = 54038989 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 54039973 and 54040000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54040043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27020006 + 27020007.

It is an arithmetic number, because the mean of its divisors is an integer number (27020007).

Almost surely, 254040013 is an apocalyptic number.

It is an amenable number.

54040013 is a deficient number, since it is larger than the sum of its proper divisors (1).

54040013 is an equidigital number, since it uses as much as digits as its factorization.

54040013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 54040013 is about 7351.1912640061. The cubic root of 54040013 is about 378.0696497358.

Adding to 54040013 its reverse (31004045), we get a palindrome (85044058).

The spelling of 54040013 in words is "fifty-four million, forty thousand, thirteen".