Base | Representation |
---|---|
bin | 1111101110100101000… |
… | …11000001111101001011 |
3 | 1220122212122011112121122 |
4 | 13313102203001331023 |
5 | 32323221221413121 |
6 | 1052131410225455 |
7 | 54020461230266 |
oct | 7672243017513 |
9 | 1818778145548 |
10 | 540403310411 |
11 | 199202642628 |
12 | 88897b8528b |
13 | 3bc62930643 |
14 | 1c2271b7cdd |
15 | e0ccc345ab |
hex | 7dd28c1f4b |
540403310411 has 2 divisors, whose sum is σ = 540403310412. Its totient is φ = 540403310410.
The previous prime is 540403310327. The next prime is 540403310413. The reversal of 540403310411 is 114013304045.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 540403310411 - 226 = 540336201547 is a prime.
Together with 540403310413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (540403310413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270201655205 + 270201655206.
It is an arithmetic number, because the mean of its divisors is an integer number (270201655206).
Almost surely, 2540403310411 is an apocalyptic number.
540403310411 is a deficient number, since it is larger than the sum of its proper divisors (1).
540403310411 is an equidigital number, since it uses as much as digits as its factorization.
540403310411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 540403310411 its reverse (114013304045), we get a palindrome (654416614456).
The spelling of 540403310411 in words is "five hundred forty billion, four hundred three million, three hundred ten thousand, four hundred eleven".
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