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540405340111 = 7135938520221
BaseRepresentation
bin1111101110100101010…
…10110001011111001111
31220122212202222122211201
413313102222301133033
532323222231340421
61052131521530331
754020514412630
oct7672252613717
91818782878751
10540405340111
111992037a956a
12888987a39a7
133bc63191450
141c227585887
15e0cced5b91
hex7dd2ab17cf

540405340111 has 8 divisors (see below), whose sum is σ = 665114264864. Its totient is φ = 427573455840.

The previous prime is 540405340109. The next prime is 540405340127. The reversal of 540405340111 is 111043504045.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 540405340111 - 21 = 540405340109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 540405340111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (540405340151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2969260020 + ... + 2969260201.

It is an arithmetic number, because the mean of its divisors is an integer number (83139283108).

Almost surely, 2540405340111 is an apocalyptic number.

540405340111 is a deficient number, since it is larger than the sum of its proper divisors (124708924753).

540405340111 is a wasteful number, since it uses less digits than its factorization.

540405340111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5938520241.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 540405340111 its reverse (111043504045), we get a palindrome (651448844156).

The spelling of 540405340111 in words is "five hundred forty billion, four hundred five million, three hundred forty thousand, one hundred eleven".

Divisors: 1 7 13 91 5938520221 41569641547 77200762873 540405340111