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540434314151 = 8323712746207
BaseRepresentation
bin1111101110101000110…
…01010011001110100111
31220122221210111200202022
413313110121103032213
532323302141023101
61052134434533355
754021315606224
oct7672431231647
91818853450668
10540434314151
11199219099156
12888a643725b
133bc69197454
141c22b36894b
15e0d080aa1b
hex7dd46533a7

540434314151 has 8 divisors (see below), whose sum is σ = 547176451584. Its totient is φ = 533697674040.

The previous prime is 540434314127. The next prime is 540434314153. The reversal of 540434314151 is 151413434045.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-540434314151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (540434314153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1176311 + ... + 1569896.

It is an arithmetic number, because the mean of its divisors is an integer number (68397056448).

Almost surely, 2540434314151 is an apocalyptic number.

540434314151 is a deficient number, since it is larger than the sum of its proper divisors (6742137433).

540434314151 is a wasteful number, since it uses less digits than its factorization.

540434314151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2748661.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 540434314151 its reverse (151413434045), we get a palindrome (691847748196).

The spelling of 540434314151 in words is "five hundred forty billion, four hundred thirty-four million, three hundred fourteen thousand, one hundred fifty-one".

Divisors: 1 83 2371 196793 2746207 227935181 6511256797 540434314151