Base | Representation |
---|---|
bin | 111101011100110011110100… |
… | …0100101001101000100110101 |
3 | 2121212211022210122222021111112 |
4 | 1322321213220211031010311 |
5 | 1031321400000233120201 |
6 | 5153332010312044405 |
7 | 221565241150131161 |
oct | 17271475045150465 |
9 | 2555738718867445 |
10 | 540521241301301 |
11 | 14725485339a3a7 |
12 | 5075877a093705 |
13 | 1a27ac1b9a9250 |
14 | 9769520c41ca1 |
15 | 42752e7e620bb |
hex | 1eb99e894d135 |
540521241301301 has 16 divisors (see below), whose sum is σ = 624297698317440. Its totient is φ = 463764004441920.
The previous prime is 540521241301253. The next prime is 540521241301333. The reversal of 540521241301301 is 103103142125045.
It is a de Polignac number, because none of the positive numbers 2k-540521241301301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (540521241201301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20644752065 + ... + 20644778246.
It is an arithmetic number, because the mean of its divisors is an integer number (39018606144840).
Almost surely, 2540521241301301 is an apocalyptic number.
It is an amenable number.
540521241301301 is a deficient number, since it is larger than the sum of its proper divisors (83776457016139).
540521241301301 is a wasteful number, since it uses less digits than its factorization.
540521241301301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41289530396.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 540521241301301 its reverse (103103142125045), we get a palindrome (643624383426346).
The spelling of 540521241301301 in words is "five hundred forty trillion, five hundred twenty-one billion, two hundred forty-one million, three hundred one thousand, three hundred one".
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