Base | Representation |
---|---|
bin | 11000100101010110100110… |
… | …11111110000111000111111 |
3 | 21002102002022211001111202102 |
4 | 30102223103133300320333 |
5 | 24041204343204104001 |
6 | 310550454011215315 |
7 | 14246464235134163 |
oct | 1422532337607077 |
9 | 232362284044672 |
10 | 54060006706751 |
11 | 162527a1498691 |
12 | 6091236a4753b |
13 | 2421ab5486486 |
14 | d4c738264ca3 |
15 | 63b358c44e6b |
hex | 312ad37f0e3f |
54060006706751 has 2 divisors, whose sum is σ = 54060006706752. Its totient is φ = 54060006706750.
The previous prime is 54060006706733. The next prime is 54060006706753. The reversal of 54060006706751 is 15760760006045.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54060006706751 is a prime.
Together with 54060006706753, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 54060006706696 and 54060006706705.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54060006706753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27030003353375 + 27030003353376.
It is an arithmetic number, because the mean of its divisors is an integer number (27030003353376).
Almost surely, 254060006706751 is an apocalyptic number.
54060006706751 is a deficient number, since it is larger than the sum of its proper divisors (1).
54060006706751 is an equidigital number, since it uses as much as digits as its factorization.
54060006706751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1058400, while the sum is 47.
The spelling of 54060006706751 in words is "fifty-four trillion, sixty billion, six million, seven hundred six thousand, seven hundred fifty-one".
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