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5408215944413 is a prime number
BaseRepresentation
bin100111010110011001011…
…0010100100110011011101
3201011000112212102201100112
41032230302302210303131
51202102011240210123
615300300004535405
71065505430015642
oct116546262446335
921130485381315
105408215944413
1117a567a9aa567
127341946b1565
13302cb98c3179
14149a8ab85dc9
1595a3056dd78
hex4eb32ca4cdd

5408215944413 has 2 divisors, whose sum is σ = 5408215944414. Its totient is φ = 5408215944412.

The previous prime is 5408215944359. The next prime is 5408215944427. The reversal of 5408215944413 is 3144495128045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4225400914084 + 1182815030329 = 2055578^2 + 1087573^2 .

It is a cyclic number.

It is not a de Polignac number, because 5408215944413 - 26 = 5408215944349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5408215944013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2704107972206 + 2704107972207.

It is an arithmetic number, because the mean of its divisors is an integer number (2704107972207).

Almost surely, 25408215944413 is an apocalyptic number.

It is an amenable number.

5408215944413 is a deficient number, since it is larger than the sum of its proper divisors (1).

5408215944413 is an equidigital number, since it uses as much as digits as its factorization.

5408215944413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2764800, while the sum is 50.

The spelling of 5408215944413 in words is "five trillion, four hundred eight billion, two hundred fifteen million, nine hundred forty-four thousand, four hundred thirteen".