Base | Representation |
---|---|
bin | 11000100110001101001111… |
… | …01011001000101001101111 |
3 | 21002111220000211210020202222 |
4 | 30103012213223020221233 |
5 | 24042144430040324411 |
6 | 311012144213305555 |
7 | 14251553114213315 |
oct | 1423064753105157 |
9 | 232456024706688 |
10 | 54089336261231 |
11 | 16264182239007 |
12 | 6096a613352bb |
13 | 24247aa98943b |
14 | d4dd1b62a0b5 |
15 | 63bec3a884db |
hex | 3131a7ac8a6f |
54089336261231 has 2 divisors, whose sum is σ = 54089336261232. Its totient is φ = 54089336261230.
The previous prime is 54089336261071. The next prime is 54089336261251. The reversal of 54089336261231 is 13216263398045.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54089336261231 - 222 = 54089332066927 is a prime.
It is a super-2 number, since 2×540893362612312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54089336261251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27044668130615 + 27044668130616.
It is an arithmetic number, because the mean of its divisors is an integer number (27044668130616).
Almost surely, 254089336261231 is an apocalyptic number.
54089336261231 is a deficient number, since it is larger than the sum of its proper divisors (1).
54089336261231 is an equidigital number, since it uses as much as digits as its factorization.
54089336261231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5598720, while the sum is 53.
The spelling of 54089336261231 in words is "fifty-four trillion, eighty-nine billion, three hundred thirty-six million, two hundred sixty-one thousand, two hundred thirty-one".
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