Base | Representation |
---|---|
bin | 11000100110001101001111… |
… | …01011001000100111001111 |
3 | 21002111220000211210020120001 |
4 | 30103012213223020213033 |
5 | 24042144430040323241 |
6 | 311012144213305131 |
7 | 14251553114212666 |
oct | 1423064753104717 |
9 | 232456024706501 |
10 | 54089336261071 |
11 | 16264182238981 |
12 | 6096a613351a7 |
13 | 24247aa989347 |
14 | d4dd1b629ddd |
15 | 63bec3a88431 |
hex | 3131a7ac89cf |
54089336261071 has 2 divisors, whose sum is σ = 54089336261072. Its totient is φ = 54089336261070.
The previous prime is 54089336261057. The next prime is 54089336261231. The reversal of 54089336261071 is 17016263398045.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54089336261071 - 27 = 54089336260943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54089336261011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27044668130535 + 27044668130536.
It is an arithmetic number, because the mean of its divisors is an integer number (27044668130536).
It is a 1-persistent number, because it is pandigital, but 2⋅54089336261071 = 108178672522142 is not.
Almost surely, 254089336261071 is an apocalyptic number.
54089336261071 is a deficient number, since it is larger than the sum of its proper divisors (1).
54089336261071 is an equidigital number, since it uses as much as digits as its factorization.
54089336261071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 55.
The spelling of 54089336261071 in words is "fifty-four trillion, eighty-nine billion, three hundred thirty-six million, two hundred sixty-one thousand, seventy-one".
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