Base | Representation |
---|---|
bin | 100111010111011010100… |
… | …0001111110111001011111 |
3 | 201011020012011001010122211 |
4 | 1032232311001332321133 |
5 | 1202121000130142120 |
6 | 15301300502421251 |
7 | 1065613531613116 |
oct | 116566501767137 |
9 | 21136164033584 |
10 | 5410401021535 |
11 | 17a65a1367324 |
12 | 7346a4431827 |
13 | 3032774cb303 |
14 | 149c1705ac7d |
15 | 95b0c2de25a |
hex | 4ebb507ee5f |
5410401021535 has 4 divisors (see below), whose sum is σ = 6492481225848. Its totient is φ = 4328320817224.
The previous prime is 5410401021521. The next prime is 5410401021563. The reversal of 5410401021535 is 5351201040145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5410401021535 - 223 = 5410392632927 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5410401021497 and 5410401021506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541040102149 + ... + 541040102158.
It is an arithmetic number, because the mean of its divisors is an integer number (1623120306462).
Almost surely, 25410401021535 is an apocalyptic number.
5410401021535 is a deficient number, since it is larger than the sum of its proper divisors (1082080204313).
5410401021535 is a wasteful number, since it uses less digits than its factorization.
5410401021535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1082080204312.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 5410401021535 in words is "five trillion, four hundred ten billion, four hundred one million, twenty-one thousand, five hundred thirty-five".
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