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54104424151 = 401134923751
BaseRepresentation
bin110010011000110111…
…111111111011010111
312011122122000112002011
4302120313333323113
51341301213033101
640504421325051
73623521005631
oct623067777327
9164578015064
1054104424151
1120a4459a728
12a59b566787
1351431c387b
1428938a7a51
151619d95751
hexc98dffed7

54104424151 has 4 divisors (see below), whose sum is σ = 54239348304. Its totient is φ = 53969500000.

The previous prime is 54104424131. The next prime is 54104424161. The reversal of 54104424151 is 15142440145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54104424151 - 211 = 54104422103 is a prime.

It is a super-2 number, since 2×541044241512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54104424131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67461475 + ... + 67462276.

It is an arithmetic number, because the mean of its divisors is an integer number (13559837076).

Almost surely, 254104424151 is an apocalyptic number.

54104424151 is a deficient number, since it is larger than the sum of its proper divisors (134924153).

54104424151 is a wasteful number, since it uses less digits than its factorization.

54104424151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134924152.

The product of its (nonzero) digits is 12800, while the sum is 31.

Adding to 54104424151 its reverse (15142440145), we get a palindrome (69246864296).

The spelling of 54104424151 in words is "fifty-four billion, one hundred four million, four hundred twenty-four thousand, one hundred fifty-one".

Divisors: 1 401 134923751 54104424151