Base | Representation |
---|---|
bin | 1111101111110010101… |
… | …10000011101111111111 |
3 | 1220201112222222020111202 |
4 | 13313321112003233333 |
5 | 32331034340040221 |
6 | 1052320141410115 |
7 | 54042553666562 |
oct | 7677126035777 |
9 | 1821488866452 |
10 | 541054221311 |
11 | 19950700361a |
12 | 88a39b6993b |
13 | 3c037743116 |
14 | 1c2898144d9 |
15 | e119e5bd0b |
hex | 7df9583bff |
541054221311 has 2 divisors, whose sum is σ = 541054221312. Its totient is φ = 541054221310.
The previous prime is 541054221263. The next prime is 541054221377. The reversal of 541054221311 is 113122450145.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 541054221311 - 230 = 539980479487 is a prime.
It is a super-3 number, since 3×5410542213113 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (541054221511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270527110655 + 270527110656.
It is an arithmetic number, because the mean of its divisors is an integer number (270527110656).
Almost surely, 2541054221311 is an apocalyptic number.
541054221311 is a deficient number, since it is larger than the sum of its proper divisors (1).
541054221311 is an equidigital number, since it uses as much as digits as its factorization.
541054221311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 541054221311 its reverse (113122450145), we get a palindrome (654176671456).
The spelling of 541054221311 in words is "five hundred forty-one billion, fifty-four million, two hundred twenty-one thousand, three hundred eleven".
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