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54111378703 = 109496434667
BaseRepresentation
bin110010011001010010…
…100001110100001111
312011200010002211221011
4302121102201310033
51341310003104303
640505230350051
73623634062404
oct623122416417
9164603084834
1054111378703
1120a4850a798
12a5a195b327
13514478a1a5
1428947982ab
15161a7bb16d
hexc994a1d0f

54111378703 has 4 divisors (see below), whose sum is σ = 54607813480. Its totient is φ = 53614943928.

The previous prime is 54111378701. The next prime is 54111378721. The reversal of 54111378703 is 30787311145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54111378703 - 21 = 54111378701 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54111378701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248217225 + ... + 248217442.

It is an arithmetic number, because the mean of its divisors is an integer number (13651953370).

Almost surely, 254111378703 is an apocalyptic number.

54111378703 is a deficient number, since it is larger than the sum of its proper divisors (496434777).

54111378703 is a wasteful number, since it uses less digits than its factorization.

54111378703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496434776.

The product of its (nonzero) digits is 70560, while the sum is 40.

Adding to 54111378703 its reverse (30787311145), we get a palindrome (84898689848).

The spelling of 54111378703 in words is "fifty-four billion, one hundred eleven million, three hundred seventy-eight thousand, seven hundred three".

Divisors: 1 109 496434667 54111378703