Base | Representation |
---|---|
bin | 110010011001100000… |
… | …110011010001110011 |
3 | 12011200101010221100201 |
4 | 302121200303101303 |
5 | 1341311432321433 |
6 | 40505442500031 |
7 | 3624010634602 |
oct | 623140632163 |
9 | 164611127321 |
10 | 54115120243 |
11 | 20a4a635878 |
12 | a5a3064617 |
13 | 514549a212 |
14 | 289508da39 |
15 | 161aca9a7d |
hex | c99833473 |
54115120243 has 4 divisors (see below), whose sum is σ = 54541223680. Its totient is φ = 53689016808.
The previous prime is 54115120231. The next prime is 54115120247. The reversal of 54115120243 is 34202151145.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34202151145 = 5 ⋅6840430229.
It is a cyclic number.
It is not a de Polignac number, because 54115120243 - 25 = 54115120211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54115120247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213051528 + ... + 213051781.
It is an arithmetic number, because the mean of its divisors is an integer number (13635305920).
Almost surely, 254115120243 is an apocalyptic number.
54115120243 is a deficient number, since it is larger than the sum of its proper divisors (426103437).
54115120243 is a wasteful number, since it uses less digits than its factorization.
54115120243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 426103436.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 54115120243 its reverse (34202151145), we get a palindrome (88317271388).
The spelling of 54115120243 in words is "fifty-four billion, one hundred fifteen million, one hundred twenty thousand, two hundred forty-three".
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