Base | Representation |
---|---|
bin | 100111011000001101100… |
… | …0000111001100011011111 |
3 | 201011101121101120112102220 |
4 | 1032300123000321203133 |
5 | 1202133001133413120 |
6 | 15302142343120423 |
7 | 1066004116036023 |
oct | 116603300714337 |
9 | 21141541515386 |
10 | 5412112013535 |
11 | 17a729a1579a7 |
12 | 734aa1443113 |
13 | 30348ab25b06 |
14 | 149d3a3a4383 |
15 | 95bac614b40 |
hex | 4ec1b0398df |
5412112013535 has 64 divisors (see below), whose sum is σ = 8757882518400. Its totient is φ = 2853871607808.
The previous prime is 5412112013533. The next prime is 5412112013551. The reversal of 5412112013535 is 5353102112145.
It is not a de Polignac number, because 5412112013535 - 21 = 5412112013533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5412112013496 and 5412112013505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5412112013533) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 289207339 + ... + 289226051.
It is an arithmetic number, because the mean of its divisors is an integer number (136841914350).
Almost surely, 25412112013535 is an apocalyptic number.
5412112013535 is a deficient number, since it is larger than the sum of its proper divisors (3345770504865).
5412112013535 is a wasteful number, since it uses less digits than its factorization.
5412112013535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19532.
The product of its (nonzero) digits is 18000, while the sum is 33.
The spelling of 5412112013535 in words is "five trillion, four hundred twelve billion, one hundred twelve million, thirteen thousand, five hundred thirty-five".
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