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54125315151 = 333075455631
BaseRepresentation
bin110010011010000111…
…101100010001001111
312011201002022220010220
4302122013230101033
51341322040041101
640510445202423
73624163405425
oct623207542117
9164632286126
1054125315151
1120a55369416
12a5a6560413
1351476296cb
142896585115
15161bb20636
hexc9a1ec44f

54125315151 has 8 divisors (see below), whose sum is σ = 72188922624. Its totient is φ = 36072625560.

The previous prime is 54125315131. The next prime is 54125315159. The reversal of 54125315151 is 15151352145.

It is a happy number.

54125315151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 54125315151 - 213 = 54125306959 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54125315159) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2717895 + ... + 2737736.

It is an arithmetic number, because the mean of its divisors is an integer number (9023615328).

Almost surely, 254125315151 is an apocalyptic number.

54125315151 is a deficient number, since it is larger than the sum of its proper divisors (18063607473).

54125315151 is a wasteful number, since it uses less digits than its factorization.

54125315151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5458941.

The product of its digits is 15000, while the sum is 33.

Adding to 54125315151 its reverse (15151352145), we get a palindrome (69276667296).

The spelling of 54125315151 in words is "fifty-four billion, one hundred twenty-five million, three hundred fifteen thousand, one hundred fifty-one".

Divisors: 1 3 3307 9921 5455631 16366893 18041771717 54125315151