Base | Representation |
---|---|
bin | 110010011010001000… |
… | …000010000010001111 |
3 | 12011201002111102102211 |
4 | 302122020002002033 |
5 | 1341322100414203 |
6 | 40510451131251 |
7 | 3624164226355 |
oct | 623210020217 |
9 | 164632442384 |
10 | 54125404303 |
11 | 20a5541a3a3 |
12 | a5a65a3b27 |
13 | 514765b169 |
14 | 28965a97d5 |
15 | 161bb3bc6d |
hex | c9a20208f |
54125404303 has 8 divisors (see below), whose sum is σ = 54505166400. Its totient is φ = 53745862560.
The previous prime is 54125404283. The next prime is 54125404331. The reversal of 54125404303 is 30340452145.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54125404303 - 25 = 54125404271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54125404343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 454333 + ... + 560953.
It is an arithmetic number, because the mean of its divisors is an integer number (6813145800).
Almost surely, 254125404303 is an apocalyptic number.
54125404303 is a deficient number, since it is larger than the sum of its proper divisors (379762097).
54125404303 is a wasteful number, since it uses less digits than its factorization.
54125404303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110177.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 54125404303 its reverse (30340452145), we get a palindrome (84465856448).
The spelling of 54125404303 in words is "fifty-four billion, one hundred twenty-five million, four hundred four thousand, three hundred three".
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