Search a number
-
+
5413002021061 = 9835506614467
BaseRepresentation
bin100111011000101000000…
…0100000000100011000101
3201011110220102021121020121
41032301100010000203011
51202141312004133221
615302410535101541
71066035144006115
oct116612004004305
921143812247217
105413002021061
1117a7706584808
127350ab5118b1
133035a033119b
14149dc267d045
1595c1081aa41
hex4ec501008c5

5413002021061 has 4 divisors (see below), whose sum is σ = 5418508636512. Its totient is φ = 5407495405612.

The previous prime is 5413002021001. The next prime is 5413002021067. The reversal of 5413002021061 is 1601202003145.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5413002021061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5413002021067) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2753306251 + ... + 2753308216.

It is an arithmetic number, because the mean of its divisors is an integer number (1354627159128).

Almost surely, 25413002021061 is an apocalyptic number.

It is an amenable number.

5413002021061 is a deficient number, since it is larger than the sum of its proper divisors (5506615451).

5413002021061 is an equidigital number, since it uses as much as digits as its factorization.

5413002021061 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5506615450.

The product of its (nonzero) digits is 1440, while the sum is 25.

The spelling of 5413002021061 in words is "five trillion, four hundred thirteen billion, two million, twenty-one thousand, sixty-one".

Divisors: 1 983 5506614467 5413002021061