Base | Representation |
---|---|
bin | 1111110000010100111… |
… | …01001011011100111101 |
3 | 1220202022000011101011211 |
4 | 13320022131023130331 |
5 | 32332131333104131 |
6 | 1052404434444421 |
7 | 54052641063346 |
oct | 7701235133475 |
9 | 1822260141154 |
10 | 541341300541 |
11 | 199644062488 |
12 | 88aba133711 |
13 | 3c082068aa2 |
14 | 1c2b59c30cd |
15 | e1352675b1 |
hex | 7e0a74b73d |
541341300541 has 2 divisors, whose sum is σ = 541341300542. Its totient is φ = 541341300540.
The previous prime is 541341300527. The next prime is 541341300641. The reversal of 541341300541 is 145003143145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 524277364900 + 17063935641 = 724070^2 + 130629^2 .
It is a cyclic number.
It is not a de Polignac number, because 541341300541 - 219 = 541340776253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (541341300641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270670650270 + 270670650271.
It is an arithmetic number, because the mean of its divisors is an integer number (270670650271).
Almost surely, 2541341300541 is an apocalyptic number.
It is an amenable number.
541341300541 is a deficient number, since it is larger than the sum of its proper divisors (1).
541341300541 is an equidigital number, since it uses as much as digits as its factorization.
541341300541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 541341300541 its reverse (145003143145), we get a palindrome (686344443686).
The spelling of 541341300541 in words is "five hundred forty-one billion, three hundred forty-one million, three hundred thousand, five hundred forty-one".
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