Base | Representation |
---|---|
bin | 100111011000110100110… |
… | …1001101111000101110111 |
3 | 201011112000100010100002001 |
4 | 1032301221221233011313 |
5 | 1202143201410411211 |
6 | 15302521313000131 |
7 | 1066051606116031 |
oct | 116615151570567 |
9 | 21145010110061 |
10 | 5413431341431 |
11 | 17a7906956533 |
12 | 7351ab253047 |
13 | 30363b26a2c9 |
14 | 14a0236b6c51 |
15 | 95c38371ac1 |
hex | 4ec69a6f177 |
5413431341431 has 2 divisors, whose sum is σ = 5413431341432. Its totient is φ = 5413431341430.
The previous prime is 5413431341419. The next prime is 5413431341473. The reversal of 5413431341431 is 1341431343145.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5413431341431 is a prime.
It is a super-2 number, since 2×54134313414312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5413431341531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2706715670715 + 2706715670716.
It is an arithmetic number, because the mean of its divisors is an integer number (2706715670716).
Almost surely, 25413431341431 is an apocalyptic number.
5413431341431 is a deficient number, since it is larger than the sum of its proper divisors (1).
5413431341431 is an equidigital number, since it uses as much as digits as its factorization.
5413431341431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 103680, while the sum is 37.
Adding to 5413431341431 its reverse (1341431343145), we get a palindrome (6754862684576).
The spelling of 5413431341431 in words is "five trillion, four hundred thirteen billion, four hundred thirty-one million, three hundred forty-one thousand, four hundred thirty-one".
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